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d^2-21d-22=0
a = 1; b = -21; c = -22;
Δ = b2-4ac
Δ = -212-4·1·(-22)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-23}{2*1}=\frac{-2}{2} =-1 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+23}{2*1}=\frac{44}{2} =22 $
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